obtain all the other zeroes of 3x⁴ + 6x³ - 2x² - 10x - 5 if the other two zeroes are √(5/3) and -√(5/3)
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It is given that √(5/3) and -√(5/3) are two zeroes of the polynomial f(x). Therefore
[ (x-√(5/3)] [x+√(5/3)] is a factor of f(x)
BUT .....
[x-√(5/3)] [x+√(5/3)] = [x^2-5/3] = 1/3 (3x^2-5)
Therefore 3x^2-5 is a factor of f(x)
Then by using long division method we have :-
(refer to the attachment)
HOPE THIS HELPS....
*CLICK ON THE RED HEART IF YOU LIKE THE ANSWER*
[ (x-√(5/3)] [x+√(5/3)] is a factor of f(x)
BUT .....
[x-√(5/3)] [x+√(5/3)] = [x^2-5/3] = 1/3 (3x^2-5)
Therefore 3x^2-5 is a factor of f(x)
Then by using long division method we have :-
(refer to the attachment)
HOPE THIS HELPS....
*CLICK ON THE RED HEART IF YOU LIKE THE ANSWER*
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