Question

Obtain all the zero of 3x3-x2-3x+1 if one of its zero is 1

Answer 1

so we can write it x-1

so now we will divide the polynomial with x-1

x-1|3x3-x2-3x+1|3x2+2x-1

    3x3-3x2

   ---------------------

            2x2-3x+1

           2x2-2x

     ----------------------

                    -x+1

                   -x+1

     -------------------------

                  0

quotient= 3x2+2x-1

now we will split the quotient to get other two zeroes

3x2+2x-1

3x2+3x-1x-1

now we will take common

3x(x+1)-1(x+1)

(x+1) (3x-1)

so all the zeroes are -1 ,1/3 and 1

Hope it helps!

Answer 2

Answer:

Step-by-step explanation:

we can write it x-1

so now we will divide the polynomial with x-1

x-1|3x3-x2-3x+1|3x2+2x-1

    3x3-3x2

   ---------------------

            2x2-3x+1

           2x2-2x

     ----------------------

                    -x+1

                   -x+1

     -------------------------

                  0

quotient= 3x2+2x-1

now we will split the quotient to get other two zeroes

3x2+2x-1

3x2+3x-1x-1

now we will take common

3x(x+1)-1(x+1)

(x+1) (3x-1)

so all the zeroes are -1 ,1/3 and 1

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