Question

obtain all the zeroes of 3x3-x2+3x+1 given that one of its zeroes is 1

Answer 1

Answer:zeros are 2 and -3

Step-by-step explanation:

hi friend,

since 1 is a zero of x³-7x+6

(x-1)is the factor of x³-7x+6

so if we divide x³-7x+6 with (x-1) then we will get x²+x-6

so we can write x³-7x+6 as (x-1)(x²+x-6)

=(x-1)(x²+3x-2x-6)

=(x-1)(x(x+3)-2(x+3))

=(x-1)(x-2)(x+3)

so the other zeros are 2 and -3

I.hope this will help u :)