Question

obtain all the zeroes of 3x4+6x3-2x2-10x-5.

Answer 1

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Quotient is x² + 2x + 1 = 0

Compare the equation with ax² + bx + c = 0

We get

a = 1 ,b = 2, c = 1

To factorize the value we have to find two value which

sum is equal to b = 2

product is a x c = 1 x 1 = 1

1 and 1 are such number which

sum is 1 + 1 = 2

product is 1 x 1 = 1

So we can write middle term 2x = x + x

We get

x² + x + x + 1 = 0

x (x +1) +1(x +1) = 0

( x + 1)( x + 1) = 0

x +1 = 0, x + 1= 0

x = -1 , x = - 1

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Answer 2

Question :-

Obtain all the zeroes of 3x⁴ + 6x³ - 2x² - 10x - 5

Solution :-

Zeroes of p(x) are ${ \sf{\sqrt{ \frac{5}{3} } , \sqrt{ \frac{ - 5}{3} }, - 1, - 1}}$

Step - by - by- Explanation :-

Refer in the attachment !