obtain all the zeroes of the polynomial 2x^4 +3x^3-15x^2-24x-8 if two of its zeros are 2 root 2 and minus 2 root 2
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Answer:
-1/2 and -1
Step-by-step explanation:
here, alpha= -2root2 and beta= 2 root2
=(x-2root2)(x+2root2)
=(x)^2-(2root2)^2
=x^2-8
by long division2x^4+3x^3-15x^2-24x-8/x^2-8 = 2x^2+3x+1
splitting 2x^2+3x+1
=2x^2+2x+x+1
=2x(x+1)+1(x+1)
=(2x+1)(x+1)
therefore the two zeroes are x=-1/2 or -1
HOPE it helps you
kartuma:
thanks a lot for your quick response and easy solution
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Hope it helps!
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