Math, asked by kartuma, 1 year ago

obtain all the zeroes of the polynomial 2x^4 +3x^3-15x^2-24x-8 if two of its zeros are 2 root 2 and minus 2 root 2​

Answers

Answered by boonddave400
10

Answer:

-1/2 and -1

Step-by-step explanation:

here, alpha= -2root2 and beta= 2 root2

=(x-2root2)(x+2root2)

=(x)^2-(2root2)^2

=x^2-8

 by long division2x^4+3x^3-15x^2-24x-8/x^2-8 = 2x^2+3x+1

splitting 2x^2+3x+1

            =2x^2+2x+x+1

            =2x(x+1)+1(x+1)

            =(2x+1)(x+1)

therefore the two zeroes are x=-1/2 or -1

HOPE it helps you


kartuma: thanks a lot for your quick response and easy solution
boonddave400: you're welcome
Answered by feba10
0

Hope it helps!

Mark me brainliest

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