obtain all the zeroes of the polynomial f(x) = 2x^4+x^3-14x^2-19x-6 if two of it's zeroes are -2 and -1
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Hi friend,
Here is your answer,
______________________________________________________________
f(x) = 2x⁴ + x³ - 14x² - 19x - 6
Two zeroes are -2 and -1
x = -2 x = -1
x+2 = 0 x+1 = 0
g(x) = (x+2)(x+1) = x²+3x+2
For taking out the other zeroes we will divide p(x) with g(x).
x²+3x+2 ) 2x⁴ + x³ - 14x² - 19x - 6( 2x² -5x - 3
2x⁴ + 6x³ + 4x²
(-) (-) (-)
-5x³ - 18x² - 19x
-5x³ - 15x² - 10x
(+) (+) (+)
-3x² - 9x - 6
-3x² - 9x - 6
0
2x² - 5x - 3 = 0
2x² + x - 6x - 3 = 0
x(2x+1) - 3(2x+1) = 0
(x-3)(2x+1) = 0
x = 3 x= ⁻¹/₂
All the zeroes are -1 , -2 , 3 and ⁻¹/₂
______________________________________________________________
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Here is your answer,
______________________________________________________________
f(x) = 2x⁴ + x³ - 14x² - 19x - 6
Two zeroes are -2 and -1
x = -2 x = -1
x+2 = 0 x+1 = 0
g(x) = (x+2)(x+1) = x²+3x+2
For taking out the other zeroes we will divide p(x) with g(x).
x²+3x+2 ) 2x⁴ + x³ - 14x² - 19x - 6( 2x² -5x - 3
2x⁴ + 6x³ + 4x²
(-) (-) (-)
-5x³ - 18x² - 19x
-5x³ - 15x² - 10x
(+) (+) (+)
-3x² - 9x - 6
-3x² - 9x - 6
0
2x² - 5x - 3 = 0
2x² + x - 6x - 3 = 0
x(2x+1) - 3(2x+1) = 0
(x-3)(2x+1) = 0
x = 3 x= ⁻¹/₂
All the zeroes are -1 , -2 , 3 and ⁻¹/₂
______________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
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