Obtain all the zeroes of the polynomial f(x) = 4x4 – 16x3 + 13x2 + 12x – 12 if its two zeroes are (underroot3/2 and -underoot3/2)
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Answer:
Other two zeroes are 2
Step-by-step explanation:
f(x) = 4x⁴ - 16x³ + 13x² + 12x - 12
Two zeroes are √3 /2 & -√3/2
g(x) = (x - √3 /2)(x + √3 /2) = x² - 3/4 = 4x² - 3
f(x) = g(x)p(x)
p(x) = ax² + bx + c
=>f(x) = (4x² - 3)(ax² + bx + c)
= 4ax⁴ + 4bx³ + x²(4c -3a) -3bx -3c
comparing with
4x⁴ - 16x³ + 13x² + 12x - 12
=> 4a = 4 => a = 1
4b = -16 => b = -4
-3c = -12 => c = 4
p(x) = x² - 4x + 4
= x² - 2x - 2x + 4
= x(x-2) -2(x -2)
= (x-2)(x-2)
= (x - 2)²
Other two zeroes are 2
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