Obtain all the zeroes of the polynomial f(x) =x4-7x3+10x2-14x-2,if two zeros are √2 and-√2
Answers
Answered by
27
Hi ,
There is an error in the question .
It may be like this.
It is given that ,
f( x ) = x⁴ - 7x³ + 10x² + 14x - 24
And
√2 , - √2 are two zeroes of f( x ).
( x - √2 ), (x + √2 ) are factors of f(x ).
( x - √2 )( x + √2 ) = x² - ( √2 )²
= x² - 2 is a factor of f( x ).
x²- 2) x⁴ - 7x³ + 10x² +14x - 24(x²-7x+12
*******x⁴ + 0 - 2x²
____________________
***********-7x³ + 12x² +14x
***†*******-7x³ + 0 + 14x
____________________
*****************12x² -24
*****************12x² - 24
____________________
***************†*** 0
Therefore ,
f(x ) = (x² - 2 ) ( x² - 7x + 12 )
= ( x² - 2 ) [ x² - 4x - 3x + 12 ]
= ( x-√2 )( x + √2 ) [ x(x-4)-3(x-4)]
= ( x - √2 )(x + √2 )( x - 4 )( x - 3 )
Required two zeroes are ,
x - 4 = 0 or x - 3 = 0
x = 4 , x = 3
√2 , - √2 , 3 , 4 are zeroes of f( x ).
I hope this helps you.
: )
There is an error in the question .
It may be like this.
It is given that ,
f( x ) = x⁴ - 7x³ + 10x² + 14x - 24
And
√2 , - √2 are two zeroes of f( x ).
( x - √2 ), (x + √2 ) are factors of f(x ).
( x - √2 )( x + √2 ) = x² - ( √2 )²
= x² - 2 is a factor of f( x ).
x²- 2) x⁴ - 7x³ + 10x² +14x - 24(x²-7x+12
*******x⁴ + 0 - 2x²
____________________
***********-7x³ + 12x² +14x
***†*******-7x³ + 0 + 14x
____________________
*****************12x² -24
*****************12x² - 24
____________________
***************†*** 0
Therefore ,
f(x ) = (x² - 2 ) ( x² - 7x + 12 )
= ( x² - 2 ) [ x² - 4x - 3x + 12 ]
= ( x-√2 )( x + √2 ) [ x(x-4)-3(x-4)]
= ( x - √2 )(x + √2 )( x - 4 )( x - 3 )
Required two zeroes are ,
x - 4 = 0 or x - 3 = 0
x = 4 , x = 3
√2 , - √2 , 3 , 4 are zeroes of f( x ).
I hope this helps you.
: )
Similar questions