Obtain all the zeroes of x^4-7x^2+12 , if two of its zeroes are √3 and -√3.
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Answer:
=(74/3)(52/2)(13/4) [LCM=12]
=(296/12)(312/12)(39/12)
=(296+312+39)/12
=647/12
=53.91
Therefore, Answer=53.91
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