Obtain all the zeroes of x4 +2x3-7x2-8x+12,if two of its zeroes are 2and - 2. Very Urgent
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Answer:
-3, 1
Step-by-step explanation:
since, 2 of its zeros are 2 and -2, therefore, the factors off the polynomial are :
(x-2) and (x+2)
Also, the product of the factors will be a factor.
so, (x-2)(x+2) = x2-4
Now, using long division, the quotient will be :
x2 + 2x - 3
now, we will factorise this using middle term splitting. Quadratic formula can also be used.
x2 + 2x -3
x2 - x + 3x - 3
x( x - 1) + 3( x - 1)
(x + 3) ( x - 1)
x = -3, 1
therefore, the the other zeros are -3 and 1
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