Obtain all the zeros of the polynomia f(x)=2x^4+x^3-14x^2-19x-6,if two of the zeros are -2 and -1
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f(x) can be written as (x+2)(x+1)(ax^2+bx+c) cause x has two roots as -2 and -1 and to get two other roots we have to find a quadratic equation.
f(x)= (x+2)(x+1)(ax^2+bx+c)
f(x) / (x+2)(x+1) = ax^2+bx+c
Do long division method which is given down in LINK
ax^2+bx+c= 2x^2 -5x -3
f(x)= (x+2)(x+1)(ax^2+bx+c)
f(x) / (x+2)(x+1) = ax^2+bx+c
Do long division method which is given down in LINK
ax^2+bx+c= 2x^2 -5x -3
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