Question

obtain all the zeros of the polynomial x^2 + 7 x + 10 and verify the relationship between the zeros and its coefficients.

Answer 1

⭐Hey guys here is your answer⭐

==============================

✔✔The given polynomial ...

x² + 7x + 10

x² + 5x + 2x + 10

x(x + 5) + 2(x + 5)

(x + 5)(x + 2 ) = 0


x + 5 = 0 ......... or......... x + 2 = 0


x = -5 ........ ........or ............x = - 2


✰The relationship between zeroes and coefficient ........


sum of zero = α + β

= (-2) + (-5)

= -7

- 7/1

- (coefficient of x)/(coefficient of x²)



Product of zero ...

= αβ

= (-2) × (-5)

= 10

= 10/1
= (constant term )/(coefficient of x²)


================================


I HOPE IT WILL HELP YOU☺️✌️


thank you✌️

Answer 2

Hey! ! !

Solution :-

x2 + 7x + 10 = (x + 2)(x + 5)

So, the value of x2 + 7x + 10 is zero when x + 2 = 0 or x + 5 = 0

Therefore, the zeroes of x2+ 7x + 10 are –2 and –5.

Sum of zeroes = -7 = –(Coefficient of x) / (Coefficient of x2)

Product of zeroes = 10 = Constant term / Coefficient of x2


☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡