Question

obtain all the zeros of the polynomials x4-7x2+12 two zero are root 3 and -root 3

Answer 1

let x^2= A

now,a^2-7a+12

by factor...

a^2-(4+3)a+12

a(a-4)-3(a-4)

(a-4) (a-3)

now the zeroes

a-4=0

a=4

and,

a-3=0

a=3

hope it help you

Answer 2

(x-✓3)(x+✓3)=
x²-3
x²-3÷x⁴-7x²+12
=x²-4
x²=-4
x=±2
so zeros are 2&-2