Question

Obtain all the zeros of x 4 + 5 x cube minus 2 x square - 48 - 48 if two of its zeros are 2 root 2 and minus 2 root 2

Answer 1

Zeroes are 2√2 and -2√2

factors are (x-2√2)(x+2√2)

=x²-(2√2)²

=x²-8

now we divide the p(x) from x²-8

x4+5x³-2x²-40x-48/x²-8

remainder comes out x²+5x+6

you can check out in the attachment how remainder comes

now we split the remainder

x²+5x+6=x²+2x+3x+6

=x(x+2)+3(x+2)

=(x+3)+(x+2)

x=-3 and x=-2

all the zeroes are 2√2,-2√2,-3and-2

Answer 2

Step-by-step explanation:

here it is if any wrong please do repl6