Question

obtain all the zeros of x^4-7x^2+12 if two of its zeroes are root 3 and -root 3

Answer 1

Answer:

x-3 and x+3 are the zeros of given polynomial

so,the product of zeros is also the zero of polynomial .

now,

(x-3)(x+3)= x^2-9

Step-by-step explanation:

= after that divide the polynomial by x^2-9

Answer 2

Step-by-step explanation:

root 3 and - root 3 are zeros of polynomial,

then x = root 3 and x = -root 3

i. e. (x -root3) and (x +root 3)

are the factors of polynomial

Now (x - root 3) x (x + root 3)

= x^2 - 3

Now divide x^4-7x^2+12 by x^2 -3 by divition method

by division algorithum

x^4 - 7x^2 +12 = (x^2 -3)(x^2-4) + 0

therefore

x^2 -4 = (x +2)( x -2)

so another factors are x =2 and x = -2 ans