Question

obtain all the zeros of x^4-7x^3+17x^2-17x+6 if two zeros are 1 and 2​

Answer 1

Given: (x-1)•(x-2) are the zeroes of p(x).

=> (x^2 - 3x + 2)

p(x) = x^4 - 7x^3 + 17x^2 - 17x + 6

Therefore, by division algorithm,

${x}^{4} - 7x {}^{3} + 17x {}^{2} - 17x + 6$

$\div \: {x}^{2} - 3x + 2$

After doing this step, you will get your answer.

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