obtain all zeroes if f (x)=2x^4-3x^3-3x+6x-2 if two zeroes are root 2 and -root 2
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Step-by-step explanation:
The given polynomial is
f(x)=2x⁴-3x³-3x²+6x-2
The given zeroes are√2 and -√2
So x+√2 and x-√2 are the factors of f(x)
So (x-√2)(x+√2)=x²-2 is a factor of f(x).
Now ,
2x⁴-3x³-3x²+6x-2
=2x⁴-4x²-3x³+6x+x²-2
=2x²(x²-2)-3x(x²-2)+1(x²-2)
=(x²-2)(2x²-3x+1)
Now factorising
2x²-3x+1
=2x²-2x-x+1
=2x(x-1)-1(x-1)
=(x-1)(2x-1)
now (x-1)(2x-1)=0
=> x-1=0 or 2x-1=0
=> x=1 or x=1/2
Thus the other two zeroes are 1 and1/2.
Hope you got it.
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