Question

obtain all zeroes of p(x)=2x⁴-3x³-5x²+9x-3 if two zeroes are -√3 and √3​

Answer 1

Solution

let,

the given problem is,

x=-√3=0

=>3=1²

=>x=3*1²

=>x=3²

x=>√3=0

=>3=-1²

=>x=3*-1²

=>x=-3²

p(3²)=2(3²)⁴-3(3²)³-5(3²)²+9(3²)-3

=2(9)⁴-3(9)³-5(9)²+9(9)-3

=2(36)-3(27)-5(18)+81-3

=72-81-90+78

=72+78-81-90

=150-9

=141

p(-3²)=2(-3²)⁴-3(-3²)³-5(-3²)²+9(-3²)-3

=2(9)⁴-3(9)³-5(9)²+9(9)-3

=2(36)-3(27)-5(18)+81-3

=72-81-90+78

=72+78-81-90

=150-9

=141

there fore LHS=RHS

I HOPE IT IS VERY HELPFUL TO YOU OK

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