obtain all zeroes of polynomial x4+7x3+7x2-35x-60,if two of its zeroes are -3 and -4.
plzzz....i need it fast
Answers
Answered by
16
√5, -√5
This is the answer
Divide the dividend with divisor as;
x"2-7x+12
This is the answer
Divide the dividend with divisor as;
x"2-7x+12
Answered by
21
Answer:
hello,
hope my ans helps
p(x)=x^4+7x^3+7x^2-35x-60
given zeros are -3,-4 they can also be written as x+3,x+4
(x+3)(x+4)=x^2+7x+12
now we divide this with p(x)
and get a quotient x^2-5
we know (a+b)(a-b)=a^2-b^2
and x^2-5 can b written as (x-root5)(x+root5)
so the zeros are -root5 and +root 5
Explanation:
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