Obtain all zeroes of the polynomial, if two of its zeroes are -root 5 and root 5
Answers
Step-by-step explanation:
Let p(x) = 2x⁴ - x³ - 11x² + 5x + 5.
Since x = √5 is a zero, x - √5 is a factor.
Since x = -√5 is a zero, x + √5 is a factor.
Hence,
(x - √5)(x + √5) is a factor.
⇒ x² - 5 is a factor.
Now, By dividing the given polynomial by x² - 5.
We can find out other factors.
Long Division Method:
x² - 5) 2x⁴ - x³ - 11x² + 5x + 5 (2x² - x - 1
2x⁴ - 10x²
---------------------------------
- x³ - x² + 5x + 5
- x³ + 5x
----------------------------------
- x² + 5
- x² + 5
----------------------------------
0
Now,
We factorize 2x² - x - 1
= 2x² - 2x - x - 1
= 2x(x - 1) - (x - 1)
= (x - 1)(2x - 1)
= (2x - 1)(x - 1) = 0
x = 1, 1/2
∴ x = (1/2) & 1 are the zeroes of p(x).
Therefore, the zeroes of p(x) are √5, -√5, (1/2), 1
Hope it helps!
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