Math, asked by rangapriya2003, 1 year ago

Obtain all zeroes of x^4+6x^3+2x^2-21x-30 if 2,-5 are zeroes

Answers

Answered by Sweetbuddy
5
Hey buddy here is ur answer !!

alpha is 2
beta is -5

alpha + beta = -b/a
alpha × beta = c/a

From the eq
a = 1
b = 6
c = 2
d = -21
e = -30

Now

-b/a = -6
c/a = 2
-d/a = 21



✌✌✌ Hope u like my process ✌✌✌



》》 BE BRAINLY 《《
Answered by Anonymous
0


x^2 + 3x + 3 has no REAL zeroes.

So,

2, - 5 are the only REAL zeroes of this expression...

If u wanna know the complex and imaginary roots, Comment.
Attachments:
Similar questions