Question

obtain all zeroes of x4 - 7 x2+12, if two zeros root3 and - root 3


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Answer 1

Answer:

x4-7x2+12

x=root3 &x=-root3

x-root3=0&x+root 3=0

(x-root3)(x+root3)=0

x2-3=0

Then by dividing x2-3 by x4-7x2+12, we get

x2-4=0

x=+-2

So,zeroes are +2,-2,+root3,-root3