obtain all zeros of the polynomial 2x^4-10x^3+5x^2+15x-12 if two of its zeros are root 3/root 2 and -root3/root2
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p(x)=2x^4-10x3+5x2+15x-12
x= -√3/2 and √13/2
Therefore,(x+√3/2)(x-√3/2)=0
x²-3/2=0
(2x2-3)/2=0
2x2-3=0
g(x)=2x2-3
Now divide p(x) by g(x)
The q(x) will be
=x²-5x+4
=x2-4x-x+4
=x(x-4)-1(x-4)
=(x-4)(x-1)
x=4 and x=1
Therefore, the other two zeroes are 4 and 1.
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