Obtain all zeros of the polynomial x^4+5x^3-6x^2-32x+32 if two of its zeros are 1 and -4
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therefore factors will be (x-1) , (x+4)
product of (x-1)(x+4)
= x(x+4)-1(x+4)
=x^2+4x-x-4
=x^2+3x-4
divide the biquadratic polynomial by x^2+3x-4 ( in the attachment)
splitting the middle term of x^2+2x-8
x^2-2x+4x-8
x(x-2)+4(x-2)
(x-2)(x+4)
therefore other two zeros are 2,-4
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