Question

Obtain an equation of current for AC voltage applied to an inductor and draw a graph of V and I​

Answer 1

Explanation:

Consider an inductor of inductance L is connected across an AC source, 

Let v = vmsin ωt --------(1),

here v - the source voltage, vm – peak voltage ,

ω - angular frequency of AC.

The self induced emf in the inductor is  According to Kirchoff’s loop rule, This indicates the current in an inductor is a function of time.  To obtain the current at any instant, we integrate the above expression. 

[because, we can show the integration constant over a cycle is zero]

  If we take  the amplitude of the current,

then i = im [-cos ωt] 

Inductive reactance is given by XL = ωL = 2πνL = 2πfL

The SI unit of XL is ohm (Ω)

The graph be drawn by u... if it helps mark as braunliedt

Answer 2

Answer:

see in your text book

Hope you understand