Question

Obtain an expression for electric field intensity at a point outside a charged conducting sphere.

Answer 1

HEY DEAR ... ✌️

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=) Let the distance body point P from the centre O is x .

Then , imagine a sphere whose radius is x and centre is O .

The point P is enclosed by a small surface dS.

If the intensity at point P is E(vector) .

Then , flux let linked with the small surface .

dØ = EdS .

Hence , the total flux linked with close surface .

Ø = ƒ EdS .


Ø = E ƒ dS .

where , ƒ dS = Area of surface ( 4πr^2 )

Ø = E (4πx^2) --------------------(1)

Acc. to gauss law .


Ø = q / εo --------------------(2)

From equations (1) and (2) .

E (4πx^2) = q / εo

E = 1 / 4πεo × q / x^2

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HOPE , IT HELPS ... ✌️

Answer 2

Read this you will understand everything!! :)