Question

obtain an expression for kinetic Theory of gases?​

Answer 1

Answer:

As total mass is J=mn so, pressure=JV(vaverage)2. By the formula of density of a gas which is ρ=JV therefore, pressure=ρ(vaverage)2. Hence, the required value of pressure exerted by the gas inside the cube is pressure=ρ(vaverage)2.

Answer 2

Answer:

By the formula Time=DistanceSpeed we will get value of time travelled by the particle by Time=2lv1. This results in the number of collisions by the same particle as v12l. Thus, change in the momentum of the same molecule will be −2mv1×v12l=−mv12l.