Question

Obtain an expression for moment of inertia of ring about a tangent in its plane.

Answer 1

Answer:

We know that, moment of inertia of a ring about its diameter is MR²/2.

Applying law of parallel forces, the moment of inertia of a ring about a tangent in the plane of the circle of the ring is -

I(tangent) = I(diameter) + MR²

I(tangent) = MR²/2 + MR²

I(tangent) = 3MR²/2

Hence, the moment of inertia of a ring about a tangent in the plane of the circle of the ring is 3MR²/2.

Explanation:

Answer 2

Answer:

see this attachment