Question

obtain an expression for period in uniform circular motion and also write expression for angular speed.​

Answer 1

Answer:

period of circular motion is given by

T = 2pi/ w

and

w = v/r

Answer 2

Answer:

The uniform circular motion  the angular speed is constant, so we can also express it in terms of the period as ω = (2π) / T

Explanation:

From the above question,

They have given :

The period of an object in uniform circular motion is the time it takes for the object to complete one full revolution around the circular path.

Thus the expression for period in uniform circular motion is:

                           T = (2πr) / v

                           F.total θ = 0

(Newton’s Second Law), the tangential acceleration is zero,

                             aθ = 0

Here the acceleration is then given by way of solely the acceleration radial element vector.

where, T is the period,

            r is the radius of the circular path and

            v is the speed of the object.

The expression for angular speed is:

            ω = Δθ / Δt

where Δθ is the change in angle in radians and

           Δt is the change in time.

The uniform circular motion  the angular speed is constant, so we can also express it in terms of the period as,

             ω = (2π) / T

where ω is the angular speed and

          T is the period.

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