Question

Obtain an expression for potential energy of three charges in an external electric field. Please answer asap​

Answer 1

Answer:

Coulombic force acting on a test charge F = $\frac{kQq}{r^{2} }$ where k = 1/4πϵ₀

Potential energy of the two charges U =  $- \int\limits {F} \, dr$

∴ U = $- \int\limits {\frac{kQq}{r^{2} } } \, dr$

U = −kQq * $- \int\limits {\frac{1}{r^{2} } } \, dr$

U = −kQq * $\frac{-1}{r}$

U = $\frac{-kQq}{r}$

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Answer 2

Two point charges 3nC and -3nC are placed at two corners of equilateral triangle of side 5cm. Find magnitude of resultant electric field at the third corner of the triangle.

If a charge of 2nC is placed at the third corner then what is the force acting