Question

obtain an expression for radius of circular path of charged particle in magnetic feild​

Answer 1

● Refer the about attachment ⬆️ for your answer☘

● Formula of the Radius of the Circular Path of a Charged Particle in a Uniform Magnetic Field. r=mvqBsinθ. r=mvsinθqB.

● Hope it helps you✌❤

Answer 2

• Let 'r' be the radius of the charged particle and 'q' be the charge.
• Since we are finding radius in a circular path, centripetal force is exerted on the circular path.
• The formula for centripetal force is given by $F = \frac{mv^{2} }{r}$  →→→(1)
• Where m is the momentum and v is the velocity.
• The Force acting on the moving charge 'q' is given by F = qvbsinθ.
• But here θ = 90°(because the force acting is perpendicular to the magnetic field)  hence sinθ = 1
• F = qvB→→→(2)
• Equating (1) and (2)
• $qvB = \frac{mv^{2} }{r}$
• v on both sides gets canceled and we get  $qB = \frac{mv}{r}$
• $r = \frac{mv}{qb}$

The expression for the radius of circular path of a charged particle is given by$r = \frac{mv}{qb}$