Obtain an expression for the electric field along the axial lineof an electric dipole
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To find electric field at point P on the axial line of the dipole, OP=r. Let E1 and E2 be electric field on P due to charges +q and −q respectively. If r>>a, then E=kr42pr=kr32p. In vector form, E =kr32p
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Consider the an electric dipole of charges +q and −q separated by distance 2a with center at O.
Goal: To find electric field at point P on the axial line of the dipole, OP=r.
Let E1 and E2 be electric field on P due to charges +q and −q respectively.
E1=(r−a)2kq along AP
E2=(r+a)2kq along BP
The resultant electric field at P, E=E1−E2 (as both E1 and E2 are in opposite direction)
E=(r−a)2kq−(r+a)2kq=kq(r2−a2)24ra
Define, p=2aq
E=k(r2−a2)22pr
If r>>a, then E=kr4
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