Question

Obtain an expression for the electric field intensity due to a uniformly charged ring r at a point on the axis of the ring.​

Answer 1

Answer:

expression of electric field on the axis of the ring is given by, E = Kqx/(R² + x²)^(3/2)

Explanation:

Answer 2

Answer:

expression of electric field on the axis of the ring is given by, E = Kqx/(R² + x²).

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