Question

Obtain an expression for the force acting on a straight conductor kept in a magnetic field​

Answer 1

Expression for the force acting on a straight conductor kept in a magnetic field:

• The basic expression for force on a moving charge in magnetic field is:

$\sf \therefore \: F = qvB \sin( \theta)$

• Now, the conductor can be considered as a charge travelling through it for a distance of length L:

$\sf \implies \: F = q \times \dfrac{L}{t} \times B \sin( \theta)$

$\sf \implies \: F = \dfrac{q}{t} \times L \times B \sin( \theta)$

$\boxed{ \sf \implies \: F = i \times L \times B \sin( \theta) }$

In vector form, we can say:

$\boxed{ \sf \implies \: \vec{F} = i ( \vec{L} \times \vec{B} ) }$

Hope It Helps.