obtain an expression for the maximum speed with which a vehicle can negotiate a curved smooth road banked at an angle theta with proper diagram
Answers
Explanation:
Consider a car of mass "m" moving on a banked road of radius 'r'. The various forces acting on the car are: (i) The weight of the car which acts vertically downwards i.e., ω = mg ....(i) (ii) The normal reaction R of the road acts perpendicular to the road. Neglect the force of friction between the tyres of the car and the road. Now resolve the normal reaction R of the road in the two components: (a) R cosθ which is equal opposite to mg i.e., R cosθ = -mg ...(ii) (b) R sinθ which acts towards the centre of the circular path and provides the necessary centripetal force ({mv2}/{r}) to the car. i.e., R sinθ = {mv2}/{r} ....(iii) Dividing (iii) by (ii) we get tanθ = v2/rg ⇒ v = (rg tanθ)1/2 which is the safe speed of the car for given value of 'r' and 'θ' on a circular banked road