Question

Obtain an expression for the orbital velocity and time period of a satellite of mass 'm' revolving around the earth at height 'x' above its surface. ​

Answer 1

Explanation:

We have:

R+x

mv

2

=

(R+x)

2

GMm

⇒v=

R+x

GM

=

R

2

GM

×

R+x

R

2

=

R+x

gR

2

because the gravitational force provides the centripetal force for revolution.