Question

obtain approximate value of ratio of nuclear radii of 26Fe56 and 92U238.what is the ratio of their nuclear densities?

Answer 1

the ratio of their nuclear density is same for all nuclei so then ans will be equal to 1

Answer 2

Answer:

The ratio of nuclear radii of given two nuclei is 0.617 and The ratio of nuclear densities of the given nuclei is 1:1

Explanation:

The given two nuclei are

$26Fe {}^{56} and \: 92U {}^{238}$

Their respective mass numbers are 56 and 238.Hence we write

$A_{1}=56 \\ A_{2}=238$

The ratio of radii is related with ratio of mass number as

$\frac{r_{1}}{r_{2}}=(\frac{A_{1}}{A_{2}}) {}^{ \frac{1}{3} }$

Substituting the given mass numbers we get the ratio as

$\frac{r_{1}}{r_{2}}=(\frac{56}{238}) {}^{ \frac{1}{3} } = 0.617$

Hence,the ratio of radius of the nuclei is 0.617.

As the nuclear density is constant for every single nuclei,the ratio of nuclear density of given nuclei is 1:1

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