Question

obtain coulomb's law with the help of Gauss's theorem.​

Answer 1

To derive Coulomb's Law from gauss law or to find the intensity of electric field due to a point charge +q at any point in space using Gauss's law ,draw a Gaussian sphere of radius r at the centre of which charge +q is located

Answer 2

Answer:

To derive Coulomb’s Law from gauss law or to find the intensity of electric field due to a point charge +q at any point in space using Gauss’s law ,draw a Gaussian sphere of radius r at the centre of which charge +q is located (Try to make the figure yourself).

All the points on this surface are equivalent and according to the symmetric consideration the electric field E has the same magnitude at every point on the surface of the sphere and it is radially outward in direction.Therefore, for a area element dS around any point P on the Gaussian surface both E and dS are directed radially outward,that is ,the angle between E and dS is zero.Therefore,

he flux passing through the area element dS ,that is,

d φ =E.dS= EdS cos 00=EdS

Hence, the total flux through the entire Gaussian sphere is obtained as,

Φ=∫EdS

Or                                φ=E∫dS

But ∫dS is the total surface area of the sphere and is equal to 4πr2,that is,

Φ=E(4πr2)                                                                  (1)

Explanation: