Question

obtain derivative of the following function
x^4+cosx-√5
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Answer 1

Answer:

Hey, the answer is in above pic .

Answer 2

SolutioN :

Let, $\sf{y\ =\ x^4\ +\ \cos\ x\ -\ \sqrt{5}} \\ \\ \mathfrak{\: \: \: \: \: \: \: \: \: \dag\ Differentiate\ \sf{y} \ wrt.\ \sf{x}} \\ \\ \\ \\ \implies \sf{\dfrac{dy}{dx}\ =\ \dfrac{d(x^4\ +\ \cos\ x\ -\ \sqrt{5})}{dx}} \\ \\ \implies \sf{\dfrac{dy}{dx}\ =\ \dfrac{d(x^4)}{dx}\ +\ \dfrac{d(\cos\ x)}{dx}\ -\ \dfrac{(5^{\frac{1}{2}})}{dx}} \\ \\ \implies \sf{\dfrac{dy}{dx}\ =\ 4x^3\ +\ (- \sin\ x)\ -\ \frac{1}{2} 5^{\frac{-1}{2}}} \\ \\ \implies \sf{\dfrac{dy}{dx}\ =\ 4x^3\ -\ sin\ x\ -\ \frac{1}{2 \sqrt{5}}}$