obtain equations of motion for constant acceleration using method of calculus
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ǫᴜᴇsᴛɪᴏɴ
ᴏʙᴛᴀɪɴ ᴇǫᴜᴀᴛɪᴏɴs ᴏғ ᴍᴏᴛɪᴏɴ ғᴏʀ ᴄᴏɴsᴛᴀɴᴛ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴜsɪɴɢ ᴍᴇᴛʜᴏᴅ ᴏғ ᴄᴀʟᴄᴜʟᴜs
ᴀɴsᴡᴇʀ:-
ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴀ ɪs ᴄᴏɴsᴛᴀɴᴛ.
ᴡᴇ ᴋɴᴏᴡ-
ᴅ2s /ᴅᴛ2 =ᴅᴠ/ᴅᴛ =ᴀ
ɪɴᴛᴇɢʀᴀᴛɪɴɢ ᴀ ᴡɪᴛʜ ʀᴇsᴘᴇᴄᴛ ᴛᴏ ᴛɪᴍᴇ ᴡɪʟʟ ʟᴇᴀᴠᴇ ᴜs ᴡɪᴛʜ ᴀɴ ᴇxᴘʀᴇssɪᴏɴ ғᴏʀ ᴠᴇʟᴏᴄɪᴛʏ, ᴠ , (ᴀs ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ɪs ᴛʜᴇ ʀᴀᴛᴇ ᴏғ ᴄʜᴀɴɢᴇ ᴏғ ᴠᴇʟᴏᴄɪᴛʏ, ᴡʀᴛ ᴛɪᴍᴇ):
ᴠ=ᴅs/ᴅᴛ = ∫ᴀ ᴅᴛ = ᴀᴛ+ᴜ,
ᴠ= ᴜ+ᴀᴛ .......(1)
ᴡʜᴇʀᴇ ᴜ ɪs ᴀ ᴄᴏɴsᴛᴀɴᴛ ᴏғ ɪɴᴛᴇɢʀᴀᴛɪᴏɴ. ɪɴ ᴄᴏɴᴛᴇxᴛ ɪᴛ ɪs ᴛʜᴇ ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ ᴀ ʙᴏᴅʏ ɪs ᴛʀᴀᴠᴇʟʟɪɴɢ ʙᴇғᴏʀᴇ ɪᴛ ᴀᴄᴄᴇʟᴇʀᴀᴛᴇs.
ɪɴᴛᴇɢʀᴀᴛɪɴɢ ᴠᴇʟᴏᴄɪᴛʏ ᴡʀᴛ ᴛɪᴍᴇ ᴡɪʟʟ ʟᴇᴀᴠᴇ ᴜs ᴡɪᴛʜ ᴀɴ ᴇxᴘʀᴇssɪᴏɴ ғᴏʀ ᴅɪsᴘʟᴀᴄᴇᴍᴇɴᴛ (ᴀs ᴠᴇʟᴏᴄɪᴛʏ ɪs ᴛʜᴇ ғɪʀsᴛ ᴅᴇʀɪᴠᴀᴛɪᴠᴇ ᴏғ ᴅɪsᴘʟᴀᴄᴇᴍᴇɴᴛ ᴍᴏᴅᴇʟʟᴇᴅ ᴀs ᴀ ғᴜɴᴄᴛɪᴏɴ ᴏғ ᴛɪᴍᴇ):
s =∫(ᴅs/ᴅᴛ) ᴅᴛ = ∫(ᴀᴛ+ᴜ) ᴅᴛ = ∫ᴀᴛ ᴅᴛ + ∫ᴜ ᴅᴛ
ʜᴇɴᴄᴇ, s= ᴜᴛ+(1/2)ᴀᴛ2 ...........(2)
ɴᴏᴛᴇ ᴛʜᴀᴛ ᴛʜɪs ᴇǫᴜᴀᴛɪᴏɴ ᴀssᴜᴍᴇs ᴅɪsᴘʟᴀᴄᴇᴍɴᴛ ɪs ᴢᴇʀᴏ ᴡʜᴇɴ ᴛɪᴍᴇ ᴛ= 0, ɪ.ᴇ. ᴛʜᴇ ᴄᴏɴsᴛᴀɴᴛ ᴏғ ɪɴᴛᴇɢʀᴀᴛɪᴏɴ ʜᴀs ʙᴇᴇɴ ɴᴇɢʟᴇᴄᴛᴇᴅ.
ғʀᴏᴍ ᴇǫᴜᴀᴛɪᴏɴ (2)
s = 1/2(2ᴜ+ᴀᴛ) ᴛ
s= 1/2(ᴜ+ᴜ+ᴀᴛ)ᴛ = 1/2(ᴜ+ᴠ)ᴛ
ᴠ2 = (ᴜ+ᴀᴛ)2 =ᴜ2 +2ᴜᴀᴛ+ᴀᴛ2
ᴠ2 = ᴜ2 +2ᴀ(ᴜᴛ+1/2 ᴀᴛ2)
= ᴜ2+2ᴀs
ᴠ2=ᴜ2+2ᴀs .............(3)
ᴡᴇ ᴋɴᴏᴡ, ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ɪs ᴛʜᴇ (ᴄʜᴀɴɢᴇ ɪɴ ᴠᴇʟᴏᴄɪᴛʏ / ᴜɴɪᴛ ᴛɪᴍᴇ).
ᴄᴏɴsɪᴅᴇʀ ᴀɴ ɪɴsᴛᴀɴᴛ ᴛɪᴍᴇ; ᴀ = (ᴅᴠ/ᴅᴛ)
ᴀ = (ᴅᴠ/ᴅᴛ)
ᴀ ∫ᴅᴛ = ∫ᴅᴠ
ɪɴᴛᴇɢʀᴀᴛɪɴɢ
ᴀ.(ᴛ₂ - ᴛ₁) = (ᴠ – ᴜ)
ʟᴇᴛ (ᴛ₂- ᴛ₁) = ᴛ
ᴛʜᴇɴ, ᴀᴛ = ᴠ - ᴜ
ᴠ = ᴜ + ᴀᴛ ɪᴛs ᴀ ᴍᴏᴛɪᴏɴ ᴇǫᴜᴀᴛɪᴏɴ ,
ɴᴏᴡ ,
ᴠ = ᴜ + ᴀᴛ
ᴍᴜʟᴛɪᴘʟʏ ʙᴏᴛʜ sɪᴅᴇs, ᴡɪᴛʜ ᴅᴛ
ᴠ x ᴅᴛ = ᴜ x ᴅᴛ + ᴀᴛ xᴅᴛ
ᴡᴇ ᴋɴᴏᴡ, ᴠ x ᴅᴛ = s { ᴅɪsᴛᴀɴᴄᴇ = sᴘᴇᴇᴅ x ᴛɪᴍᴇ }
ᴜsɪɴɢ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇǫᴜᴀᴛɪᴏɴ
s = ᴜ(ᴛ₂-ᴛ₁) + ᴀ(ᴛ₂-ᴛ₁)²/(2)
ᴛʜᴇʀᴇғᴏʀᴇ,
s = ᴜᴛ + (1/2)ᴀᴛ² ᴍᴏᴛɪᴏɴ, ᴇǫᴜᴀᴛɪᴏɴ.
ᴀʟsᴏ
s = ᴜᴛ + (1/2)ᴀᴛ² _(1)
ᴠ = ᴜ + ᴀᴛ
sǫᴜᴀʀɪɴɢ ʙᴏᴛʜ sɪᴅᴇs,
ᴠ² = ᴜ² + ᴀ²ᴛ² + 2ᴜᴀᴛ
ᴠ² = ᴜ² + 2ᴀ {(1/2) ᴀᴛ² + ᴜᴛ}
ғʀᴏᴍ ᴇǫᴜ (1)
ᴠ² = ᴜ² + 2ᴀs ᴍᴏᴛɪᴏɴ ᴇǫᴜᴀᴛɪᴏɴ,
ᴏʀ ᴡᴇ ᴋɴᴏᴡ,
ᴠx(ᴅᴠ/ᴅx) = ᴀ
∫ᴠ ᴅᴠ = ᴀ ∫ᴅx
ɪɴᴛᴇɢʀᴀᴛᴇ ʙᴏᴛʜ sɪᴅᴇs,
(ᴠ² - ᴜ²) = 2ᴀ(x₂ - x₁)
ʟᴇᴛ (x₂ - x₁) = s
ᴠ² = ᴜ² + 2ᴀs ᴛʜɪʀᴅ ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ