obtain expression for frequency of a conical pendulam
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Let's use Newton's second law (ΣF = ma) to derive an expression for:
Let's use Newton's second law (ΣF = ma) to derive an expression for:the angle θ in terms of the tangential velocity of the mass, the radius of the circular path (r) and the acceleration due to gravity (g)t.
Let's use Newton's second law (ΣF = ma) to derive an expression for:the angle θ in terms of the tangential velocity of the mass, the radius of the circular path (r) and the acceleration due to gravity (g)t.he height of the conical pendulum in terms of ω2 and g.
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- Let's use Newton's second law (ΣF = ma) to derive an expression for:the angle θ in terms of the tangential velocity of the mass, the radius of the circular path (r) and the acceleration due to gravity (g)t.he height of the conical pendulum in terms of ω2 and g.
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