Obtain first ix iterations of the bisection method to find an approximation to 3
√
31.
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Answer:
Actually if they would have given 2 as option then as per me if i am applying Binary search then the answer should then have be 2.
I illustrate it below:
1,2,3,4,5,6,7,8,9
First Binary Search Algo:
Binary Search(a,x)
{
do{
mid=floor(beg+end/2);
if(a[mid]==x)
return TRUE
else if(x>a[mid])
lo=mid+1
else
hi=mid-1
}while(beg<=end)
}
Considering array indices startted at 1 and went to 9
lo=1
hi=9
mid=floor(1+9/2)=5 @ f(5) !=0 Fail
lo=1
hi=4 (its pritty intuitive why i chose lower half!)
mid=floor(1+4/2)=2 @ f(2)=0 <----tada!!! we have got it
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