Physics, asked by ayushkhokharjaat, 1 year ago

Obtain mirror formula for concave mirror.

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Answered by Anonymous
5

\Large\underline\mathfrak{Question}

Obtain mirror formula for concave mirror.

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→ Check the attachment first provided with answer.

→ We need to Learn about Sign Conventions before deriving mirror formula as it involve "The sign conversations.

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\Large\bold\star\underline{\underline\textbf{Mirror formula\:}}

→ See the attachment .

→ Consider an object AB lying beyond the principal focus F of a concave mirror.

→ Let BK and BL be the two incident rays which meet at point B' after reflection from the mirror.

→ A'B' be the image of object AB.

→ Draw KN perpendicular to principal axis.

→ Now ∆ NKF and ∆ A'B'F are similar, therefore

» A'B' / KN = A' F /NF.....................(1)

→ When aperture of mirror is small then point N is very close to P. So, NF ≈ PF (approx) and KN ≈ AB

→ Equation (1) becomes,

A'B / AB = A'F / PF ..........................(2).

→ Also ∆ ABC and ∆ A'B'C are similar, therefore

A'B' / AB = A'C / AC ........................(3).

→ From equations (2) and (3), we have

A'F / PF = A'C / AC

(Or)

PA' - PF / PF = PC - PA' / PA -PC

..................(4)

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→ Using Sign Conventions , We have,

» PA' = - v

» PA' = - v » PF = - f

» PA' = - v » PF = - f» PC = R = - 2f

» PA' = - v » PF = - f» PC = R = - 2f» PA = - u

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→ So , Equation (4) becomes

 \frac{ - v \:  + \:  f  \: }{ - f}  =  \frac{ - 2f \:  +   \: v \: }{ - u \:  +  \: 2f}

» uv - 2vf - uf + 2f² = 2f² - vf

» uv - uf = vf.............(5)

Dividing equation (5) by uvf , we get

 \frac{1}{f}  -  \frac{1}{u}  =  \frac{1}{v}

Or

</p><p> \frac{1}{f }  =  \frac{1}{u}  +  \frac{1}{v}

This equation is called mirror formula.

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Hope it helped u.

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