Question

obtain quadratic equation if roots are -3 & -7?​

Answer 1

Answer:

x= -3 or x= -7

=> (x+3)(x+7)=0

$= > {x}^{2} + 3x + 7x + 21 = 0 \\ </h2><h2> = > \: {x}^{2} + 10x + 21 = 0$

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Hope it helps you ☆▪☆

Answer 2

Answer:

$\alpha + \beta = - 3 - 7 = - 10 \\ \alpha \beta = - 3 \times - 7 = 21 \\ x {}^{2} ( \alpha + \beta ) \times x + \alpha \beta = 0 \\ x {}^{2} - ( - 10x) + 21 = 0 \\ x {}^{2} + 10x + 21 = 0$

I hope it will help u.....