obtain such that their HCF is 20 and their LCM is 300
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We have to find two numbers such that HCF of two numbers is 20 and LCM of that numbers is 300. [ where a and b are co-prime numbers. ] Therefore two required numbers are 60, 100
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Question-
Find no. whose HCF =20 and LCM= 300
Solution-
Product of two no.= 20x300
= 6000
Now, we can obtain many pairs of numbers whose Hcf= 20,Lcm= 300.
Our answer==> 60,100
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