Obtain the average atomic mass of neon. Refer image for question and equation.
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Given,
atomic mass of = 19.99u
abundance = 90.51 %
atomic mass of = 20.99u
abundance = 0.27 %
atomic mass of = 21.99u
abundance = 9.22 %
average atomic mass = (19.99 × 90.51 + 20.99 × 0.27 + 21.99 × 9.22)/100
= (1809.2949 + 5.6673 + 202.7478)/100
= 2017.71/100
= 20.1771u
atomic mass of = 19.99u
abundance = 90.51 %
atomic mass of = 20.99u
abundance = 0.27 %
atomic mass of = 21.99u
abundance = 9.22 %
average atomic mass = (19.99 × 90.51 + 20.99 × 0.27 + 21.99 × 9.22)/100
= (1809.2949 + 5.6673 + 202.7478)/100
= 2017.71/100
= 20.1771u
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