Obtain the balancing condition of whetstone,s Network
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In balanced Wheatstone's bridge, zero current flow through galvanometer. Means while applying Kirchoff's law we can neglet
No current flows through galvanometer G if circuit is balanced.
Applying Kirchoff's law to
1 ) Mesh ABDA,
-I1R1 + (I-I1)R4 = 0
I1R1 = (I-I1)R4 ….(1)
2 ) Mesh BCDB,
-I1R2 + (I-I1)R3 = 0
I1R2 = (I-I1)R3 ….(2)
Dividing (1) by (2),
I1R1 / I1R2 = (I-I1)R4 / (I-I1)R3
R1/R2 = R4/R3
Explanation:
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