Obtain The Express The Following For Maximum Hight
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Explanation:
The maximum height, ymax, can be found from the equation:
vy 2 = voy2 + 2 ay (y - yo)
yo = 0, and, when the projectile is at the maximum height, vy = 0.
Solving the equation for ymax gives:
ymax = - voy2 /(2 ay)
Plugging in voy = vo sin(q) and ay = -g, gives:
ymax = vo2sin2(q) /(2 g)
where g = 9.8 m/s2
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