Physics, asked by maskiez2776, 11 months ago

Obtain The Express The Following For Maximum Hight

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Answered by 1259442
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Answer:

Explanation:

The maximum height, ymax, can be found from the equation:

vy 2 = voy2 + 2 ay (y - yo)

yo = 0, and, when the projectile is at the maximum height, vy = 0.

Solving the equation for ymax gives:

ymax = - voy2 /(2 ay)

Plugging in voy = vo sin(q) and ay = -g, gives:

ymax = vo2sin2(q) /(2 g)

where g = 9.8 m/s2

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