Question

obtain the expression for maximum height
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Answer 1

Answer:

vx=ucosθvy2−uy2=2ayvy=0(atmaxheightH)uy=usinθay=−gHPuttingthesevalues,0=(usinθ)2−2gHH=2gu2sin2θ

Answer 2

Answer:

The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g .