Obtain the expression for minimum angle of deviation for a ray of light passing through a glass prism. please give the answer......
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A=Prism angle, δ=Angle of deviation, i1=Angle of incidence, i2=Angle of emergent.
In the case of minimum deviation,∠r1=∠r2=∠r.
A=∠r1+∠r2.
A+δ=i1+i2 (∵ In the case of minimum deviation.
i1=i2=i and δ=δm)
BTS army!!!
A=Prism angle, δ=Angle of deviation, i1=Angle of incidence, i2=Angle of emergent.
In the case of minimum deviation,∠r1=∠r2=∠r.
A=∠r1+∠r2.
A+δ=i1+i2 (∵ In the case of minimum deviation.
i1=i2=i and δ=δm)
BTS army!!!
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